**Abstract**

The predicted IBU contribution when adding hops at flameout is usually zero. This is in conflict with widespread experience, which shows that adding hops at flameout does add significant bitterness. This blog post proposes a modification to the Tinseth IBU formula to account for hops added late in the boil and/or at flameout. This new metric is referred to as “maximum IBU” (or “mIBU”), for reasons explained below. I’ve created an on-line calculator for the mIBU method here: https://jphosom.github.io/alchemyoverlord/ with a description of this calculator in the blog post An On-Line Calculator for the mIBU Technique. John Koopmans has made an implementation of the mIBU method available in an Excel document.

While the technique described here is still correct, I’ve since developed another IBU calculator (called SMPH) that accounts separately for the contribution of isomerized alpha acids and auxiliary bittering compounds to the IBU. The SMPH model incorporates the post-flameout technique described here.

**Problem
**

*Introduction*

If one takes a standard formula for predicting IBUs, such as Tinseth’s, hops additions at flameout contribute nothing to the final IBU measurement. Tinseth had “access to some handy tools and knowledgeable friends at the USDA hop labs and the Flavor Perception labs at Oregon State University,” and he has “had quite a few worts and beers analyzed.” His formula is very widely used, presumably because it does as good or better a job at predicting bitterness levels compared with other available formulas. So it’s worth taking his work and formula very seriously.

However, a quick glance at various internet sources indicates that this is one area where formulas and observations do not always line up. In a BYO article from Mar/Apr 2013, it is reported that large systems (15 bbl = 465 G = 1760 liters) get 16% utilization from hops added at flameout, while smaller systems (11 G or 42 liters) get around 10% utilization. In a discussion at probrewer, one user says “Matt Brynildson, a former hop chemist, claims to get 22% whirlpool utilization at Firestone Walker (50-bbl system) and to have gotten 15% whirlpool utilization on a 10-bbl brewpub system”. In another discussion at probrewer, utilization rates between 13% and ~30% are reported for whirlpool additions. In short, we have reported post-flameout utilization (and consequent bitterness) ranging from 10% to 30%, and a lot of numbers in between. There is apparently *some* utilization happening after flameout; it’s just not quite clear how much. The question then becomes how to model post-flameout utilization in the prediction of IBUs.

**Solution**

*Approach*

Hop utilization decreases as a function of temperature, with more utilization at boiling and less utilization at lower temperatures. (I’ve seen claims that utilization drops to zero at around 180°F (82°C), and claims that the decrease in utilization follows an Arrhenius equation. In a separate blog post, I look at relative utilization as a function of temperature.) It’s also very clear that when the gas (or electricity) of the boil is turned off, the temperature of the wort doesn’t instantaneously drop to room temperature. (If you start your wort chiller immediately at flameout and have a small volume, then you’ll probably get pretty close to the Tinseth estimation of 0 IBUs with a hops addition at flameout, but most people leave the hops in the naturally-cooling wort for at least some time before forced cooling.) Therefore, there is (usually) additional utilization happening after flameout, and the degree of this additional utilization depends on when the hops were added and how quickly the wort cools. It seems possible to take Tinseth’s formula for IBUs, combine it with a measure of how utilization is affected by temperature, and calculate the additional IBUs that occur after flameout… and that’s exactly what this section does.

*Tinseth’s IBU Formula*

I’ll use Glenn Tinseth’s formula for predicting IBUs in this post, because this formula is “considered very accurate” (BeerSmith: Calculating Hop Bitterness: How much Hops to Use?), but also simply because I haven’t yet worked as much with the formulas from Rager or Garetz. Tinseth’s formula is as follows:

IBU = U(BG,t_{1}) × D(AA,W,V) |
[1] |

U(BG,t_{1}) = b(BG) × f(t_{1}) |
[2] |

D(AA,W,V) = AA × W × 1000 / V |
[3] |

b(BG) = 1.65 × 0.000125^{(BG − 1)} |
[4] |

f(t_{1}) = (1 − e^{(-0.04t1)}) / 4.15 |
[5] |

where *U*(*BG*,*t*_{1}) is the hop utilization (which is a function of both boil gravity and time), *D*(*AA*,*W*,*V*) is the density of alpha acids in the wort (in mg/l, a function of the alpha-acid rating, weight of hops, and post-boil volume of wort), *b*(*BG*) is a “bigness factor” that is a function of the boil gravity (*BG*), *f*(*t*_{1}) is a “time factor” that predicts the isomerization of alpha acids as a function of time (in minutes) (*t*_{1}), *AA* is the alpha-acid rating (in percent) of the hops added, *W* is the weight of the hops (in grams), and *V* is the volume of the wort (in liters). (Generally I’ll try to use both metric and Imperial units in this post… according to WordPress, about half of the people reading this are from the U.S. and half are not. In this paragraph, I’ll use only metric for simplicity.) I use *t*_{1} to denote time, instead of just *t*, because another time variable, *t*_{2}, will be used later. Tinseth suggests “fiddling with 4.15 if necessary to match your system; only play with the other three [constants (1.65, 0.000125, and -0.04)] if you like to muck around.” One complication is that time is usually measured from the point at which hops are added until flameout. Because of this, any hops that are in the wort after flameout are predicted to contribute nothing to the final IBU value, even though they are in near-boiling wort for some amount of time.

(Glenn Tinseth, according to an e-mail exchange I had with him, took small samples every 5 or 10 minutes and quickly cooled those samples in glass sample jars in a refrigerator, so the amount of utilization that he obtained after taking each sample was minimal. This is why the estimated utilization for a boil time of zero minutes using the Tinseth formula is zero.)

I’ll refer to *U*(*BG*,*t*_{1}) simply as “utilization”; this is the utilization that we believe also decreases as a function of temperature, which isn’t indicated in the current formula. The utilization is a unitless number less than or equal to 1; usually it’s below 0.3. Utilization normally represents the relative amount of alpha acids added to the wort that (a) get converted into isomerized alpha acids and (b) end up in the finished beer. The Tinseth formula (and other formulas) have a direct relationship between utilization, isomerized alpha acids, and IBUs. This is an oversimplification, since other hop components (oxidized alpha and beta acids, and polyphenols) are not part of the utilization equation, but they still contribute to bitterness and the measured IBU value. The utilization in these IBU formulas therefore implicitly includes the effects of these other components on the IBU value. This oversimplification usually works out fairly well, though, for typical hop rates and boiling times.

*Plot of Utilization*

We can plot the utilization in Equation [2] as a function of time, starting at time 0 and increasing with the length of time that the hops are in the kettle:

This function shows the *cumulative* effect of utilization after the hops have spent a certain amount of time in the kettle, from *t*_{1}=0 (hops addition) until some final time. If we add hops at 40 minutes before flameout to a wort with gravity 1.060, the hops spend 40 minutes in the boiling wort, and cumulative utilization during those 40 minutes is 0.185. (Here we’re assuming that the utilization drops immediately to zero at flameout.) We can find the value of 0.185 by simply looking at the utilization value at the 40-minute mark for a boil gravity of 1.060. Time 0 is when hops are added to the pot, and the selected time (e.g. 40 minutes) is when we remove the hops from the kettle (perhaps at flameout) and/or bring utilization down to zero.

*Instantaneous Utilization*

Next, we can look at the instantaneous effect of hop utilization at any point in time, by taking the derivative (or slope) of the utilization function:

U(BG,t_{1}) = 1.65 x 0.000125^{(BG−1)} × (1 − e^{(-0.04t1)}) / 4.15 |
[6] |

dU(BG,t_{1})/dt_{1} = -1.65 x 0.000125^{(BG−1)} × -0.04e^{(-0.04t1)}/4.15 |
[7] |

where the formula for *U*(*BG*,*t*_{1}) in Equation [6] is the same (but simplified) utilization function in Equation [2], and *dU*(*BG*,*t*_{1})/*dt _{1}* in Equation [7] is the derivative of this utilization with respect to time. The instantaneous utilization function in Equation [7] can be plotted like this:

This graph tells us how much hop utilization is happening, for example, at exactly the 40-minute mark (in this case, 0.001873 utilization/minute for BG 1.060). (Note that the *rate* of utilization is highest when the hops are first added, and this rate decreases as the hops stay in the boil longer. Tinseth explains that the shape of the utilization curve is because “alpha acid isomerization is a first order, or more likely, a pseudo first order chemical reaction.“) If we integrate all of these instantaneous utilization values, from time 0 (when we add the hops) up to the time when we remove the hops, we end up with the original utilization value. For example, if we have a hops addition at 40 minutes for a boil gravity of 1.060, we can compute the area under the instantaneous-utilization curve from 0 to 40 (shown below in green), and that area will equal the total utilization at 40 minutes from the original utilization formula (0.185).

We can also integrate only over a specific time range, to determine how much utilization is happening during a particular period of time; for example, we can look at the utilization between 40 minutes and 50 minutes for a boil gravity of 1.060, which is the area below shown in blue:

*Additional Utilization*

Let’s pretend for a minute that when flameout happens, we forget to turn off the heat for exactly 10 minutes and the boil keeps going. When we realize our mistake, we immediately and quickly cool the wort (which has an average boil gravity of 1.060). In this case, utilization keeps happening after our intended flameout; what was a hops addition at 40 minutes becomes really a hops addition at 50 minutes, because the hops are in the boiling wort for an additional 10 minutes:

We can look at the utilization of our *intended* time (40 minutes) and our *extra* time (10 minutes, between 40 minutes and 50 minutes) separately, by finding the areas under the two separate curves. In this case, the utilization up to 40 minutes is 0.185 (just as we’d expect), and (by integration of the instantaneous utilization over the range from 40 to 50 minutes) the additional utilization during the final 10 minutes is 0.015. The total utilization is therefore 0.200. What really happens (in most cases, when we’re paying attention) is that we do remember to turn off the heat at flameout, but the wort remains hot for some period of time. We’re not getting maximum utilization after flameout, but we are getting some while the wort is still hot.

*Decrease in Utilization as a Function of Temperature and Time*.

After flameout, utilization is happening (unless we immediately and very quickly cool the wort), but not at the full rate. It would be nice to have some function of utilization that shows how it decreases after flameout, as the temperature slowly decreases. We can create such a function from two functions: (a) the temperature of the wort as a function of time after flameout, and (b) the degree of hop utilization as a function of temperature.

If we measure the temperature of the wort after flameout at one-minute intervals, we can map these data points to a function. Figure 6 shows such a series of measurements (from mIBU Experiment #3) and a function that predicts temperature after flameout with an exponential decay function.

This temperature-decay function is described in more detail in the blog post Predicting Wort Temperature After Flameout. When working in Fahrenheit, the function is *T*(*t*_{2}) = 96.66 × exp(-*b* × *t*_{2}) + 115.52, when working in Celsius, the function is *T*(*t*_{2}) = 53.70 × exp(-*b* × *t*_{2}) + 46.40, and when working in Kelvin, the function is *T*(*t*_{2}) = 53.70 × exp(-*b* × *t*_{2}) + 319.55. (The notation “exp()” indicates the exponential function, where exp(*x*) = e* ^{x}* = 2.71828

*.) Regardless of the temperature units,*

^{x}*b*= (0.0002925 ×

*effectiveArea*/

*volume*) + .00538 and

*effectiveArea*= (

*surfaceArea*×

*openingArea*)

^{0.5}. The parameter

*volume*is the volume of the wort in liters,

*surfaceArea*is the surface area of wort exposed to air (in square centimeters), and

*openingArea*is the area of the opening in the kettle (in square centimeters). Both

*surfaceArea*and

*openingArea*can be computed from the diameter of the kettle and the diameter of the opening, using the formula

*area*= π × (

*diameter*/2)

^{2}or 3.14159 ×

*radius*

^{2}. (Note that if you’re working in British Imperial units, it’s easiest to convert volume and diameter to metric.)

Next, we need a function that describes the relative amount of utilization as a function of temperature, with utilization at boiling defined to have a value of 1.0. Based on the analysis from this blog post, we can use this function: *U _{rel}*(

*T*) = 2.39×10

^{11}e

^{-9773/T}(where

*T*is temperature in degrees Kelvin).

We can then plot the relative utilization *as a function of time*, as the temperature decreases after flameout, with 1.3 G of wort cooling in an open kettle, using the predicted temperature in Kelvin at each time point (based on the wort volume, kettle diameter, and kettle opening diameter) and the relative utilization at each predicted temperature:

The next formulas summarize the mappings between temperature, time, and relative utilization, working in degrees Kelvin:

U(_{rel}T) = 2.39×10^{11} e^{-9773/T} |
relative utilization as a function of temperature (T is in degrees Kelvin) |
[8] |

T(t_{2}) = 53.70 × exp(-b × t_{2}) + 319.55 |
temperature (in degrees Kelvin) as a function of time, if t_{2} ≥ 0. The parameter b is defined in the text. |
[9] |

U(_{rel}t_{2}) = 2.39×10^{11} e^{-9773/(53.70 × exp(-b × t2) + 319.55)} |
relative utilization as a function of time, if t_{2} ≥ 0. |
[10] |

U(_{rel}t_{2}) = 1 |
relative utilization as a function of time, if t_{2} < 0 |
[11] |

Equation [8] is the relative utilization as a function of temperature; Equation [9] is the predicted temperature of the wort as a function of time after flameout. Equation [10] combines Equations [8] and [9] for time after flameout greater than or equal to 0. Equation [11] specifies that before flameout (during the boil), the relative utilization is maximum (i.e. the value predicted by the Tinseth formula).

Note that these formulas may explain why we get different opinions on how much utilization there is after flameout; the rate at which the wort temperature decreases is dependent on volume, kettle diameter, and kettle opening. Larger systems with more volume will cool more slowly, yielding increased utilization. Two systems that have the same volume but different types of kettles will cool differently, again yielding different utilization. If you want to know how the IBUs in a beer will change as you “scale up” from a smaller batch size to a larger size, you can use the different volumes and kettle parameters to estimate the increase in utilization and IBUs.

*Combining Functions*

Now we have a complete picture of instantaneous utilization as a function of time. Before flameout, we use the instantaneous utilization of Equation [7], where *t*_{1} is the amount of time that the hops are in the kettle. After flameout, we can combine our measure of instantaneous utilization with *how much* utilization is happening at each instant, by taking the pointwise product of the two formulas. For example, if the instantaneous utilization at boiling is 0.001873 and the relative utilization at 208°F (97.8°C) is 0.90, then the instantaneous utilization at this temperature is 0.001873 × 0.90 = 0.0016857.

Since we measure time with two different starting points in the different equations (when hops are added, *t*_{1}, and when flameout happens, at which point *t*_{2} = 0), we need to convert from one to the other. If we define *t*_{f} to be the time, relative to *t*_{1}, at which flameout happens, then *t*_{2} = *t*_{1} − *t*_{f}. We can then use *t*_{1} and *t*_{f} in the same formula to measure these two time points on the same scale. We can write this complete picture with the following formulas:

deg(t_{1}) ⋅ dU(BG,t_{1})/dt_{1} = -1.65 x 0.000125^{(BG−1)} × -0.04e^{(-0.04t1)}/4.15 |
if t_{1} < t_{f} |
[12] |

deg(t_{1}) ⋅ dU(BG,t_{1})/dt_{1} = U(_{rel}t_{1} − t_{f}) × (-1.65 x 0.000125^{(BG−1)} × -0.04e^{(-0.04t1)}/4.15) |
if t_{1} ≥ t but_{f}before forced cooling |
[13] |

deg(t_{1}) ⋅ dU(BG,t_{1})/dt_{1} = 0 |
after forced cooling | [14] |

Going back to our example, let’s say we turn off the heat at 40 minutes (as intended) and let the kettle cool naturally for 10 minutes. (There’s nothing magical about 10 minutes; in this example, we wait 10 minutes after flameout before turning on the wort chiller, which then quickly cools the wort to room temperature. We could just as easily wait 5 minutes or 20 minutes.) The graph below shows the instantaneous utilization happening at boiling between 0 and 40 minutes (in green), and the instantaneous utilization that happens between 40 and 50 minutes (in blue) that takes into account the temperature decrease after flameout. After 50 minutes, the wort chiller kicks in and quickly cools the wort. The green area is the same as before, but the blue area is reduced relative to Figure 5.

Figure 8. Area under instant utilization, with cooling between 40 and 50 minutes.

If we integrate this plot (or function) from flameout until the utilization becomes zero (usually due to forced cooling), we can determine the total utilization that occurs after flameout. This value can then be added to the utilization that occurs before flameout (our standard formula), and then we can compute the total IBUs that result from the combined utilization, pre- and post-flameout.

*Adjustment for Non-IAA Components*

Now we get to a tricky part. The Tinseth equation has only the hops AA rating, hops weight, boil time, wort volume, and specific gravity as inputs. From these values, it’s estimating the IBU value. While the concentration of isomerized alpha acids (IAA) is the *primary* contributor to the IBU value, other factors also influence the IBU (especially at short boil times): oxidized alpha and beta acids, and polyphenols. These factors can be referred to collectively as non-IAA components (or auxiliary bittering compounds (ABC)), and they’re not explicitly addressed in the Tinseth model. These non-IAA components do not require isomerization, and so they affect the IBU value quickly and, it seems, their concentrations remain somewhat constant during the boil. In another blog post, I estimate that the non-IAA components account for more than half of the Tinseth utilization formula at 5 minutes (even with well-preserved hops). Therefore, I think that the Tinseth equation underestimates IBU values below 5 minutes, because it doesn’t account for non-IAA components; at 5 minutes and above, the Tinseth utilization function is modeling the combination of both IAA and non-IAA components. (The Rager equation has a roughly constant utilization of 0.05 between 0 and 5 minutes, which may be accounting for the contribution of non-IAA components to the IBU.)

Having the Tinseth equation model a combination of IAA and non-IAA components usually doesn’t matter. In this case, however, we are modeling the degree of *alpha-acid* utilization as a function of temperature, not the degree of utilization of alpha acids plus non-IAA components. The primary problem is that the non-IAA components are much less dependent on temperature than the rate of isomerization. As a further complication, the non-IAA components have a very different time-dependent contribution to IBUs than the isomerization reaction of alpha acids. It’s difficult to combine this function with a time-independent but temperature-dependent function of relative alpha-acid utilization.

An expedient solution is to set the relative utilization to 1.0 between 0 and 5 minutes. By doing this, we are implicitly saying that during the first five minutes of the hop addition, all of the IBU contribution is coming from non-IAA components and that they contribute the same amount regardless of temperature. After five minutes of steeping, the contribution of isomerized alpha acids dominates, and we switch to the temperature-dependent relative utilization of alpha acids. This is an over-simplification of what’s really happening, but it requires no modifications to the original Tinseth equation, and it corresponds better with our understanding of the various contributions to the IBU value. If hops are added more than 5 minutes before flameout, this modification has no impact on estimated IBU values, regardless of any post-boil steeping; only close-to-flameout hop additions are impacted. This solution is not exact or accurate, but better than ignoring non-IAA components entirely.

*Final Algorithm*

The final formula for measuring IBUs after flameout might get complicated. Because we don’t really need the infinite precision that a mathematical formula gives us, I’ll provide an algorithm for computing IBUs with the necessary modifications to the Tinseth formula. In this case, we’ll just use computer magic to compute the area under a curve with an arbitrary degree of precision.

Here is the algorithm for computing total IBUs, including the contribution of post-flameout utilization, in C-like pseudocode, with precision to at least two decimal places:

// the following code assumes we know the boil gravity (BG), post-boil volume // (volume_gallons, in gallons), the weight of hops added (hopsWeight_oz, // in ounces), the AA value of the hops (AA, in percent, with values from // 0 to 100), the time of the hops in the boil (boilTime_min, in minutes), // when (relative to flameout) there is forced cooling (coolTime_min, in // minutes), the kettle diameter (kettleDiameter_inches, in inches), and // the kettle opening diameter (openingDiameter_inches, in inches). // The forced cooling is assumed here to be instantaneous. volume_liters = volume_gallons * 3.78541; hopsWeight_grams = hopsWeight_oz * 28.3495; kettleDiameter_cm = kettleDiameter_inches * 2.54; openingDiameter_cm = openingDiameter_inches * 2.54; AA_maxOne = AA / 100.0; boilUtilization = computeBoilUtilization(boilTime_min, BG); postBoilUtilization = computePostBoilUtilization(boilTime_min, BG, coolTime_min, volume_liters, kettleDiameter_cm, openingDiameter_cm); totalUtilization = boilUtilization + postBoilUtilization; IBU = (totalUtilization * AA_maxOne * hopsWeight_grams * 1000.0) / volume_liters; print("total IBUs, including post-flameout, is %f\n", IBU); procedure computeBoilUtilization(boilTime_min, BG) { bignessFactor = 1.65 * pow(0.000125, (BG-1.0)); boilTimeFactor = (1.0 - exp(-0.04 * boilTime_min)) / 4.15; decimalAArating = bignessFactor * boilTimeFactor; return(decimalAArating); } procedure computePostBoilUtilization(boilTime_min, BG, coolTime_min, volume_liters, kettleDiameter_cm, openingDiameter_cm) { integrationTime = 0.001; decimalAArating = 0.0; for (t = boilTime_min; t < boilTime_min + coolTime_min; t = t + integrationTime) { dU = -1.65 * pow(0.000125, (BG-1.0)) * -0.04 * exp(-0.04*t) / 4.15; surfaceArea_cm2 = 3.14159 * (kettleDiameter_cm/2.0) * (kettleDiameter_cm/2.0); openingArea_cm2 = 3.14159 * (openingDiameter_cm/2.0) * (openingDiameter_cm/2.0); effectiveArea_cm2 = sqrt(surfaceArea_cm2 * openingArea_cm2); b = (0.0002925 * effectiveArea_cm2 / volume_liters) + 0.00538; temp_degK = 53.70 * exp(-1.0 * b * (t - boilTime_min)) + 319.55; degreeOfUtilization = 2.39*pow(10.0,11.0)*exp(-9773.0/temp_degK); if (t < 5.0) degreeOfUtilization = 1.0; // account for nonIAA components combinedValue = dU * degreeOfUtilization; decimalAArating = decimalAArating + (combinedValue * integrationTime); } return(decimalAArating); }

Note that if we quickly cool the wort at flameout, then `coolTime_min`

is zero and we get the same result as the original Tinseth formula. Only when we have some time between flameout and forced cooling do we get additional IBUs.

For those of you who would like to implement this but aren’t programmers, I’ve created a summary blog post and an on-line calculator here: https://jphosom.github.io/alchemyoverlord/. If you have any questions or would like help in implementing it yourself, let me know by sending an e-mail to the name associated with this blog (no spaces) at yahoo.

John Koopmans has also made an implementation of the mIBU method available in an Excel document. In order to use this document to predict IBU values, you’ll need to enable macros. The document contains a Visual Basic macro that is required in order to implement the loop over time values.

**Examples **

Because the instantaneous utilization is greatest when the hops are first added, the effect of bitterness contributions after flameout is more pronounced for late hop additions than for early additions. If we have 2 oz (56.7 g) of 10% AA hops added at 6 minutes before flameout in 5.25 G (19.87 liters) of wort with specific gravity 1.060, the kettle then cools naturally for an additional 10 minutes, and we then force-cool the wort quickly, we get 0.0493 utilization predicted for the 6-minute boil and an additional 0.0431 utilization predicted after flameout. The combined predicted utilization of 0.0924 is nearly double that of the prediction that doesn’t take into account post-flameout utilization, resulting in a predicted IBU of 26 instead of 14.

For the same case, but with hops added at 60 minutes instead of 6 minutes before flameout, we get 57 IBU predicted by the standard Tinseth formula and 59 IBUs predicted by the combination of boil utilization and post-boil utilization.

As another example, we can add the same hops at flameout and perform forced cooling at 30 minutes after flameout. In this case, we get 8.0% utilization for a wort with boil gravity 1.060. If we double the wort volume (and keep all other parameters the same), we get 10.0% utilization. We can get 8% utilization and 23 IBUs from 2 oz (56.7 g) of 10% AA hops added at flameout with a specific gravity of 1.060 and post-boil volume of 5.25 gallons (19.87 liters), with forced cooling after 30 minutes. If we keep the kettle covered after flameout, the temperature will decrease more slowly, and we will get 13% utilization and 36 IBUs from this flameout addition.

**What’s in a Name**

One problem with this formula for predicting IBUs is that the predicted values will almost always be larger than what we’re used to… sometimes, quite a bit larger. I like to aim for an IBU:OG ratio (e.g. 1.0) when planning a recipe, and I’ve developed some intuition for what this ratio means in practice using the Tinseth formula. When the predicted IBU values become larger by some amount, I’ve lost my point of reference.

I’ve decided to name this combined measure of boil and post-boil IBUs “maximum IBU” or “mIBU”, because it represents a (roughly) maximum bound on IBU values in finished beer. IBUs will decrease as the pH is lowered, with an increased hopping rate, with poorly-stored hops, and over time, but mIBU values should be *approximately* the highest observed IBU values for a batch of fully-fermented beer. From a discussion at Brewsmith, by user brewfun: “filtration and packaging [can] reduce IBU persistence by 85%”… “it’s a lot easier to lose IBUs than to gain them.” Note that Tinseth developed his formula using beer, not wort, and so the decrease in IBUs due to fermentation is included in the Tinseth equation.

Using a different name allows a separation between the IBUs predicted by the Tinseth formula that I’ve grown accustomed to, and these new, larger values. I will use both terms in my brewing, and hopefully over time I’ll get a sense of the perceived bitterness of mIBU values and an intuitive feeling for the relationship between Tinseth IBUs and mIBUs. The separation of terms will hopefully avoid confusion. Is “mIBU” a great name? No, actually I don’t much care for the name itself, but it’s a useful way to identify this IBU estimation method.

**Data/Supporting Evidence**

I’ve conducted a series of three experiments to evaluate the ideas in this blog post. The first experiment simply confirmed that I can get measured IBU values that correlate reasonably well with the Tinseth formula when cooling the wort immediately after flameout and when using fully-fermented beer. (I think this experiment would have turned out better if I’d used very fresh hops.) The second experiment looked at the relative degree of utilization as a function of temperature, and provided the reasoning behind Equation 8. The third experiment compared measured IBU values with values predicted by the Tinseth equation and the mIBU approach. This experiment confirmed that the mIBU approach yields, for at least this one set of data, better IBU estimates at short (or zero) boil times. Another result from this experiment was that I needed to account for the age of the beer and the alpha-acid concentration at the start of the boil, in order for the recommended Tinseth scaling factor of 4.15 to provide a good fit to the data.

To get measured IBU values, I sent samples to Analysis Laboratory. Scott Bruslind from Analysis Laboratory was very responsive and encouraging, providing a full set of measurements (including gravity, pH, and attenuation, in addition to IBUs) as well as alpha-acid measurements of hops.

**Conclusion**

This post has presented an algorithm for modifying Tinseth’s IBU formula to predict post-flameout IBU contributions. In addition to the standard parameters needed to predict IBUs (specific gravity, post-boil volume, etc.), this algorithm needs as input (a) the wort volume, kettle diameter, and kettle opening diameter in order to predict wort temperature as a function of time, and (b) the time at which forced cooling begins.

**Acknowledgements**

I’d like to thank Prof. Glenn Tinseth for his prompt and very helpful answers to a number of questions I had about his formula. I’d also like to thank Scott Bruslind for his encouragement and the analysis of hops and IBUs.

Michael MazeI converted this to R and played around with it a bit.

I was getting more or less the same utilization numbers as you but super high ibu numbers, until I turned 1000 into 100 in the following line:

IBU = (totalUtilization * AA_maxOne * hopsWeight_grams * 1000.0)

(Is this right?)

This way If I input 1 oz of 10%AA hops at 1.050 @ 10 minutes in 6 gallons with 10 minutes forced cooling, I get 9 IBUs and 12.6% utilization.

Makes sense, right?

At any rate, really helpful – much more so than the “assume 10% utilization if you’re a homebrewer” rule of thumb. I’m going to try to brew a saison with only high AA hops in the hopstand, I’ll see if it will hit the right balance. Thanks for this!

Alchemy OverlordPost authorThis seems close, and the utilization is right, but something seems off… the factor of 1000 is correct in the formula, and I get a larger (m)IBU value than you do. I suspect there’s some issue in converting Imperial units (oz, gallons) to metric, maybe? If I apply the formula as given in the algorithm, with 1.0 oz of 10% AA hops in 1.050 wort @ 10 minutes in 6 gallons, with 10 minutes forced cooling and the cooling function used in the post, I get 15.77 mIBU (compared with the 9 mIBU that you’re getting), with 8.36% utilization in the 10 minutes before flameout and 4.27% utilization in the 10 minutes after flameout. (The combined utilization, 8.36% + 4.27% = 12.63%, is slightly less than in Table A (12.8%), because the algorithm used to generate the table includes an additional consideration that the wort does not cool instantly at forced cooling; the difference in utilization is negligible.) I’m not sure why we’d have the same utilization factor but end up with different IBU values, since that part should be straightforward application of Tinseth’s formula. It’s always possible that I have a bug, but I’ve gone over the code several times now from different angles, and it looks correct to me. Let me know if you get stumped; maybe we can trade code and resolve the difference that way. You can e-mail me at the name of this blog, no spaces, at yahoo. At any rate, I hope the saison turns out well!

HernanHi! First of all congratulations on your work! Its really very interesting.

One question… in the github project (https://jphosom.github.io/alchemyoverlord/) the Kettle Diameter in cm. is limited to 500cm. Is there a particular reason for this?

Thank you very much and excuse me for my bad english.

Alchemy OverlordPost authorThanks for your kind words! To answer your question: I put upper and lower limits on all of the input fields so that a user doesn’t inadvertently enter a bogus value. I had thought 500cm (16 feet) would be a good upper limit for kettle diameter, but I’ve now changed it to 1000cm (33 feet). If you’d like an even higher limit or other changes, just let me know.

Thiago Vaevitca CoutinhoHello Alchemy Overlord.

Congratulations for your article, sensational. I was amazed.

I am trying to calculate the values manually but I have some doubts to resolve with you.

The first is:

For the calculation of temp_Degk below, what value should I consider for the variables (t) and (boilTime_min)?

temp_degK = 53.70 * exp (-1.0 * b * (t – boilTime_min)) + 319.55

The second:

In the algorithm described I did not observe at any time which formula uses the variable cooltime_min

Thanks in advance for your attention.

Cheers!

Alchemy OverlordPost authorHi, thank you for saying such nice things. I hope I can answer your questions.

For the first question, boilTime_min is the duration for which the hops are boiled, in minutes (the “_min” indicates “minutes”, not “minimum” as one might think). This boil time is the duration from when the hops are added to the boiling wort up until when the heat is turned off. So, if you add the hops at 20 minutes before flameout, boilTime_min is 20. Then the wort may sit there for a number of minutes before starting “forced cooling”, e.g. with an immersion chiller. The time between stopping the boil and starting the immersion chiller is called “coolTime_min” in the code. The variable t that you ask about is increased by 0.001 (integrationTime) in the sample code at every execution of the loop. If we have a boil time of 20 minutes and forced cooling starts 10 minutes after we stop the boil, then boilTime_min = 20 and coolTime_min = 10. So t starts out equal to boilTime_min (e.g. 20.0) when that block of code is first executed. At the end of the block of code, t is incremented by 0.001 and becomes 20.001. Because 20.001 is less than 20+10 (boilTime_min + coolTime_min), that block of code is executed again and the second time through this block, t = 20.001. The third time through this block of code, t = 20.002, and this keeps going until t = 30.0, at which point the code stops looping and returns the result. Using a computer, it’s easy to do this. Manually, you’d need to integrate the utilization (which is a function of time and temperature) from t=20.0 to t=30.0.

For the second question, coolTime_min is used only to decide when to stop the loop that accumulates utilization values every 0.001 minutes. So, you’re right, it’s not used in any formula. If this were done manually by integration, coolTime_min would be in the upper limit of the integration formula.

I hope this answers your questions. If not, please respond to this comment or email me directly. Cheers!

alanmHi Overlord. Great article, thanks!

Tinseth fits his curve based on “finished volume of beer” which seems to be generally read as “volume into fermenter” ie after both boil-off _and_ any trub&chiller loss. This is certainly how BeerSmith interprets it, the online calculators that Mr Tinseth wrote and linked to seem (to me) to back this up.

Your calculations here are using post-boil volume which is unlikely to be the same. I don’t think it’s much of a problem since you are calculating _utilisation_ not IBUs, but when you plug that utilisation into the Tinseth formula (line “IBU = …” in the code snippet) shouldn’t you be using the “finished volume of beer” there instead of the same post-boil vol used in your earlier calculations.

Alchemy OverlordPost authorThanks for bringing this up! It’s an important question because the value used for volume in the equation can have a big impact on the IBU value. I think the term that is used, “finished volume”, is somewhat ambiguous. The online calculators from Prof. Tinseth that I’m aware of refer to “final volume”, which (to me) is also ambiguous.

Some of this ambiguity may be due to the different reasons why post-boil volume and final/finished volume might be different. One reason is lost wort, e.g. trub loss. Another reason is when doing a partial boil, e.g. brewing 2.5 gallons (9.5 liters) and then diluting with the same volume of water.

The IBU is an indirect measure of the concentration of bitter compounds in the beer. Therefore, if you have 5 G (19 liters) of wort and only ferment half of that volume, you will not get double the IBUs, as would be implied when using the volume after losses. You can take a small sample of post-boil wort, ferment that tiny volume and the remainder separately, and the IBUs in the two cases will be the same… the concentration is not affected, even though the volumes are very different. On the other hand, if you add 2.5 G (9.5 liters) of water to 2.5 G (9.5 liters) of wort, the concentration will be halved and so the IBUs will also be halved. So I think the correct meaning for “volume” in the formula is the post-boil volume, regardless of lost wort, and then adjusted by any added water.

But even if this logic is compelling, in some sense the more important question is “what did Prof. Tinseth mean” in his equation. A few years ago I decided to ask him this in order to settle the issue in my mind.

My e-mail to him was: “I’ve always thought that since the formula is calculating mg/l of alpha acids, that the “volume of finished beer” in the denominator refers to the post-boil volume, since it’s computing the concentration of alpha acids that is independent of racking or other losses. John Palmer, in his book How To Brew, however, says that you should use the “recipe volume”, e.g. 5 gallons if your final volume (after losses) is 5 gallons: http://howtobrew.com/book/ section-1/hops/hop-bittering- calculations

I guess the correct answer depends on how you constructed the formula… if you used the recipe volume, then that would be the correct number to use. So, my question is, should we be using “post-boil volume” or “recipe” volume in your equation?”

His response was: “Your intuition is correct. We are concerned with the mg/L and any portions of a liter lost post boil doesn’t affect the calculation. Post boil volume is correct.”

It’s hard to get a more definitive answer on the topic than from Prof. Tinseth himself, but if you still think there is ambiguity in the interpretation, I’m happy to continue the discussion.

alanmThanks for the detailed response. As you say it’s hard to get a more definitive answer and I’m happy to leave it at that.

1. I stand corrected referring to him as “Mr” :)

2. And as another correction to me earlier post: BeerSmith in fact uses “Pre boil vol minus trub&chiller loss” as the input volume, and on top of that uses pre-boil gravity instead of average wort gravity. Which is pretty odd, although I guess the two errors cancel each other out to some extent.

Alchemy OverlordPost authorI think “Mr” is still correct; I like to refer to him with the honorific out of respect. He’s had such a big impact on brewing, and I’ve pestered him over the years with various questions and he has always been gracious, informative, and quick to respond. My metaphorical hat is off to him.

I haven’t used BeerSmith so I can’t comment on it, but that does seem strange.

Cheers!

JoséThank you for your work and this very interesting post. My question is have you developed a similar model for first-wort hopping?

Alchemy OverlordPost authorUnfortunately, no. I’ve never worked with first-wort hopping.